2x^2-32x-10=0

Solution for 2x^2-32x-10=0 equation:

2x^2-32x-10=0

a = 2; b = -32; c = -10;
Δ = b2-4ac
Δ = -322-4·2·(-10)
Δ = 1104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1104}=\sqrt{16*69}=\sqrt{16}*\sqrt{69}=4\sqrt{69}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-4\sqrt{69}}{2*2}=\frac{32-4\sqrt{69}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+4\sqrt{69}}{2*2}=\frac{32+4\sqrt{69}}{4}
$